CHEMISTRY SHENANIGANS

In today's class, we did a lab. Last class, we had to complete the prelab which involved our prediction for the outcome of the experiment.

The Experimental Design: 2.00 g of Strontium nitrate is dissolved in 50mL of water and then reacted with excess Copper (II) sulphate (3.00g). The product is a precipitate (Strontium sulphate and Copper (II) nitrate. After mixing the solutions, the precipitate will be seprated by filtration, dried and weighed.

My group's prediction results:

1. What is the balanced chemical equation for this reaction?
Sr(NO₃)₂ + CuSO₄ --> SrSO₄ + Cu(NO₃)₂

2. If 2.00 g of Strontium nitrate completely reacts, how many grams of Strontium sulphate should be produced?
2.00 g Sr(NO₃)₂ x (1 mol/211.6g) x (1 mol/SrSO₄/1 mol Sr(NO₃)₂) x 183.7g/mol = 1.74 g



We completed the first part of the lab (dissolving the chemicals, forming a precipitate, and seprating it through filtration) and the second half (drying and weighing) will occur next class.